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JavaScript 获取url参数 替换url参数

发布时间::2019-08-12 09:19    浏览次
  1. // 有时需要从整个url种获取参数,不能只那search段,所以正则加了个?,以支持整个url获取参数
  2. functiongetUrlParamVal(name) {
  3. var reg = newRegExp("(^|[&?])" + name + "=([^&]*)(&|$)");
  4. var r = getUrl().match(reg);
  5. if (r != null) {
  6. returnunescape(r[2]);
  7.        }
  8. returnnull;
  9. }
  1. // 替换参数
  2. functionreplaceUrlParamVal(url, paramName, replaceWith) {
  3. var re = eval('/('+ paramName+'=)([^&]*)/gi');
  4. var nUrl = url.replace(re,paramName+'='+replaceWith);
  5. return nUrl;


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